3x^2+42x=-147

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Solution for 3x^2+42x=-147 equation: 



3x^2+42x=-147

We move all terms to the left:

3x^2+42x-(-147)=0

We add all the numbers together, and all the variables

3x^2+42x+147=0

a = 3; b = 42; c = +147;
Δ = b2-4ac
Δ = 422-4·3·147
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-42}{6}=-7$

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